What is (1+1)\times (1/2+0) ?

The solution to (1+1)\times (1/2+0) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1+1)\times (1/2+0)

(1 + 1) \cdot (\frac{1}{2} + 0)

1

Solution steps

(1 + 1) (\frac{1}{2} + 0)

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + 1) : 2

1 + 1

1 + 1 = 2

= 2

= 2 (\frac{1}{2} + 0)

Calculate within parentheses

(\frac{1}{2} + 0) : \frac{1}{2}

\frac{1}{2} + 0

\frac{1}{2} + 0 = \frac{1}{2}

\frac{1}{2} + 0

\frac{1}{2} + 0 = \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

= 2 \cdot \frac{1}{2}

Multiply and divide (left to right)

2 \cdot \frac{1}{2} : 1

2 \cdot \frac{1}{2}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} \cdot \frac{1}{2}

Cross-cancel common factor:

2

= 1

= 1

4 [(32 - 5^{2}) - (2^{3} - 1)]

[75 + 25 \times 4^{2}] - 3 \times 3^{3}

3 - 4 - 6 - 10 + 2

- 4 (- 1)^{2} + 6

3 \times 1 0^{0}