What is (-5)^0+8^1+(-3)^3 ?

The solution to (-5)^0+8^1+(-3)^3 is -18

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(-5)^0+8^1+(-3)^3

(- 5)^{0} + 8^{1} + (- 3)^{3}

- 18

Solution steps

(- 5)^{0} + 8^{1} + (- 3)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 5)^{0} : 1

(- 5)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{0} = 5^{0} = 1

= 1

= 1 + 8^{1} + (- 3)^{3}

Calculate exponents

8^{1} : 8

8^{1}

8^{1} = 8

= 8

= 1 + 8 + (- 3)^{3}

Calculate exponents

(- 3)^{3} : - 27

(- 3)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3)^{3} = - 3^{3} = - 27

= - 27

= 1 + 8 - 27

Add and subtract (left to right)

1 + 8 - 27 : - 18

1 + 8 - 27

1 + 8 = 9

= 9 - 27

9 - 27 = - 18

= - 18

= - 18

[(66 \div 11)^{2} - 6] \cdot 5 + 5

- (- 1 - 3)^{2} - 2

- 9 - (- 8) - 15 - 17 - (- 32) + 0

- 32 (5) + 256

20 + 4 \times 5