What is 10-2[6+(8-4)^2]\times 5 ?

The solution to 10-2[6+(8-4)^2]\times 5 is -210

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10-2[6+(8-4)^2]\times 5

10 - 2 [6 + (8 - 4)^{2}] \cdot 5

- 210

Solution steps

10 - 2 [6 + (8 - 4)^{2}] \cdot 5

Follow the PEMDAS order of operations

Calculate within parentheses

[6 + (8 - 4)^{2}] : 22

6 + (8 - 4)^{2}

Calculate within parentheses

(8 - 4) : 4

8 - 4

8 - 4 = 4

= 4

= 6 + 4^{2}

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 6 + 16

Add and subtract (left to right)

6 + 16 : 22

6 + 16

6 + 16 = 22

= 22

= 22

= 10 - 2 \cdot 22 \cdot 5

Multiply and divide (left to right)

2 \cdot 22 \cdot 5 : 220

2 \cdot 22 \cdot 5

2 \cdot 22 = 44

= 44 \cdot 5

44 \cdot 5 = 220

= 220

= 10 - 220

Add and subtract (left to right)

10 - 220 : - 210

10 - 220

10 - 220 = - 210

= - 210

= - 210

4003 - 3468 \div 34 + 104

- \frac{3}{2} \times 3 + 5

(9 - 3) \times 2 + 3 \div (5 - 2)

\frac{3 ^{2} \cdot 5 ^{0}}{2 ^{3}}

4 + [[(5 \times 2) - 12] \div 2]

What is 10-2[6+(8-4)^2]\times 5 ?
The solution to 10-2[6+(8-4)^2]\times 5 is -210