What is (-1)^2+2(-1)-3 ?

The solution to (-1)^2+2(-1)-3 is -4

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(-1)^2+2(-1)-3

(- 1)^{2} + 2 (- 1) - 3

- 4

Solution steps

(- 1)^{2} + 2 (- 1) - 3

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 + 2 (- 1) - 3

Multiply and divide (left to right)

2 (- 1) : - 2

2 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 1) = - 2 \cdot 1 = - 2

= - 2

= 1 - 2 - 3

Add and subtract (left to right)

1 - 2 - 3 : - 4

1 - 2 - 3

1 - 2 = - 1

= - 1 - 3

- 1 - 3 = - 4

= - 4

= - 4

7 \times 7 - 48 \div 2

1^{2} + 4

(- 1)^{2} + 2

(- 1)^{2} + 4

2 (- 3) - 3