What is (2+1/4)(1-4/5) ?

The solution to (2+1/4)(1-4/5) is 9/20

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(2+1/4)(1-4/5)

(2 + \frac{1}{4}) (1 - \frac{4}{5})

\frac{9}{20}

Solution steps

(2 + \frac{1}{4}) (1 - \frac{4}{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(2 + \frac{1}{4}) : \frac{9}{4}

2 + \frac{1}{4}

2 + \frac{1}{4} = \frac{9}{4}

2 + \frac{1}{4}

Convert element to fraction:

2 = \frac{2 \cdot 4}{4}

= \frac{2 \cdot 4}{4} + \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 4 + 1}{4}

2 \cdot 4 + 1 = 9

2 \cdot 4 + 1

Multiply the numbers:

2 \cdot 4 = 8

= 8 + 1

Add the numbers:

8 + 1 = 9

= 9

= \frac{9}{4}

= \frac{9}{4}

= \frac{9}{4} (1 - \frac{4}{5})

Calculate within parentheses

(1 - \frac{4}{5}) : \frac{1}{5}

1 - \frac{4}{5}

1 - \frac{4}{5} = \frac{1}{5}

1 - \frac{4}{5}

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{4}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 4}{5}

1 \cdot 5 - 4 = 1

1 \cdot 5 - 4

Multiply the numbers:

1 \cdot 5 = 5

= 5 - 4

Subtract the numbers:

5 - 4 = 1

= 1

= \frac{1}{5}

= \frac{1}{5}

= \frac{9}{4} \cdot \frac{1}{5}

Multiply and divide (left to right)

\frac{9}{4} \cdot \frac{1}{5} : \frac{9}{20}

\frac{9}{4} \cdot \frac{1}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{9 \cdot 1}{4 \cdot 5}

Multiply the numbers:

9 \cdot 1 = 9

= \frac{9}{4 \cdot 5}

Multiply the numbers:

4 \cdot 5 = 20

= \frac{9}{20}

= \frac{9}{20}

\frac{6 ^{5}}{2 ^{5} \cdot 3 ^{3}}

- (1)^{2} + 1

20 + (4 - 6)^{2}

(+ 4) + (- 6) + (- 8) + (+ 10) + (- 2)

2 \cdot (\frac{4}{3} - \frac{5}{6})