What is 2 2/4*(-4) 1/3 ?

The solution to 2 2/4*(-4) 1/3 is -10/3

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2 2/4*(-4) 1/3

2 \frac{2}{4} \cdot (- 4) \frac{1}{3}

- \frac{10}{3}

Solution steps

2 \frac{2}{4} \cdot (- 4) \frac{1}{3}

Convert mixed numbers to improper fractions:

2 \frac{2}{4} = \frac{10}{4}

2 \frac{2}{4}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{2}{4} = \frac{2 \cdot 4 + 2}{4}

= \frac{10}{4}

= \frac{10}{4} \cdot (- 4) \frac{1}{3}

\frac{10}{4} = \frac{5}{2}

Cancel the common factor:

2

\frac{5}{2}

= \frac{5}{2} (- 4) \frac{1}{3}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{5}{2} (- 4) \frac{1}{3} : - \frac{10}{3}

\frac{5}{2} (- 4) \frac{1}{3}

\frac{5}{2} (- 4) = - 10

\frac{5}{2} (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{5}{2} (- 4) = - \frac{5}{2} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= - \frac{5}{2} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{5}{2} \cdot \frac{4}{1} = \frac{5 \cdot 4}{2 \cdot 1}

= - \frac{5 \cdot 4}{2 \cdot 1}

Cancel

\frac{5 \cdot 4}{2 \cdot 1} : 10

\frac{5 \cdot 4}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{5 \cdot 4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 5 \cdot 2

Multiply the numbers:

5 \cdot 2 = 10

= 10

= - 10

= - 10 \cdot \frac{1}{3}

- 10 \frac{1}{3} = - \frac{10}{3}

- 10 \cdot \frac{1}{3}

Convert element to fraction:

10 = \frac{10}{1}

= - \frac{10}{1} \cdot \frac{1}{3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{10}{1} \cdot \frac{1}{3} = \frac{10 \cdot 1}{1 \cdot 3}

= - \frac{10 \cdot 1}{1 \cdot 3}

Multiply the numbers:

10 \cdot 1 = 10

= - \frac{10}{1 \cdot 3}

Multiply the numbers:

1 \cdot 3 = 3

= - \frac{10}{3}

= - \frac{10}{3}

= - \frac{10}{3}

9 \times (- 6 + (- 2))

9^{2} + 2 6^{2}

- 8 \cdot 3^{2} + 14 + 2 - 4^{2}

5 \times 9 + (10 \div 5) - 2 + 6

9 \div 3 - [(28 - 10) - (9 - 2)]