What is (3)^4-20(3)-21 ?

The solution to (3)^4-20(3)-21 is 0

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(3)^4-20(3)-21

(3)^{4} - 20 (3) - 21

0

Solution steps

(3)^{4} - 20 (3) - 21

Follow the PEMDAS order of operations

Calculate exponents

(3)^{4} : 81

(3)^{4}

(3)^{4} = 81

= 81

= 81 - 20 (3) - 21

Multiply and divide (left to right)

20 (3) : 60

20 (3)

Apply rule:

(a) = a

(3) = 3

= 20 \cdot 3

Multiply the numbers:

20 \cdot 3 = 60

= 60

= 81 - 60 - 21

Add and subtract (left to right)

81 - 60 - 21 : 0

81 - 60 - 21

81 - 60 = 21

= 21 - 21

21 - 21 = 0

= 0

= 0

\frac{2}{( 1 + 1 ) ^{3}}

(3 \cdot 2)^{4} - (5 \cdot 2)^{3}

5^{2} - 23 + 18 - 15 + 40 \div 8 - 30

15 + 2 {4 [(16 + 4) + 3 (- 9 - 2 - 1) 3]}

(5 + 3 \times 2 \div 6 - 4) \times (4 \div 2 - 3)