What is -1/25 (5)^2+4/5 (5)+2 ?

The solution to -1/25 (5)^2+4/5 (5)+2 is 5

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-1/25 (5)^2+4/5 (5)+2

- \frac{1}{25} (5)^{2} + \frac{4}{5} (5) + 2

5

Solution steps

- \frac{1}{25} (5)^{2} + \frac{4}{5} (5) + 2

Follow the PEMDAS order of operations

Calculate exponents

(5)^{2} : 25

(5)^{2}

(5)^{2} = 25

= 25

= - \frac{1}{25} \cdot 25 + \frac{4}{5} (5) + 2

Multiply and divide (left to right)

- \frac{1}{25} \cdot 25 : - 1

- \frac{1}{25} \cdot 25

Convert element to fraction:

25 = \frac{25}{1}

= - \frac{1}{25} \cdot \frac{25}{1}

Cross-cancel common factor:

25

= - 1

= - 1 + \frac{4}{5} (5) + 2

Multiply and divide (left to right)

\frac{4}{5} (5) : 4

\frac{4}{5} (5)

Apply rule:

(a) = a

(5) = 5

= \frac{4}{5} \cdot 5

Convert element to fraction:

5 = \frac{5}{1}

= \frac{4}{5} \cdot \frac{5}{1}

Cross-cancel common factor:

5

= \frac{4}{1}

Divide the numbers:

\frac{4}{1} = 4

= 4

= - 1 + 4 + 2

Add and subtract (left to right)

- 1 + 4 + 2 : 5

- 1 + 4 + 2

- 1 + 4 = 3

= 3 + 2

3 + 2 = 5

= 5

= 5

3 + 7 \times 3^{2} - 5 \times 6

6 - 3 \times 2^{3}

- 4 - (+ 24) \div (+ 1 - 9) - (- 1 - 2)

2^{6} - 2^{3}

(2 \cdot 4) + 6 + 2