What is 4-3[4-2(6-3)]\div 2 ?

The solution to 4-3[4-2(6-3)]\div 2 is 7

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4-3[4-2(6-3)]\div 2

4 - 3 [4 - 2 (6 - 3)] \div 2

7

Solution steps

4 - 3 [4 - 2 (6 - 3)] \div 2

Follow the PEMDAS order of operations

Calculate within parentheses

[4 - 2 (6 - 3)] : - 2

4 - 2 (6 - 3)

Calculate within parentheses

(6 - 3) : 3

6 - 3

6 - 3 = 3

= 3

= 4 - 2 \cdot 3

Multiply and divide (left to right)

2 \cdot 3 : 6

2 \cdot 3

2 \cdot 3 = 6

= 6

= 4 - 6

Add and subtract (left to right)

4 - 6 : - 2

4 - 6

4 - 6 = - 2

= - 2

= - 2

= 4 - 3 (- 2) \div 2

Multiply and divide (left to right)

3 (- 2) \div 2 : - 3

3 (- 2) \div 2

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 2) = - 3 \cdot 2 = - 6

= - 6 \div 2

Apply rule

(- a) \div b = - a \div b

(- 6) \div 2 = - 6 \div 2 = - 3

= - 3

= 4 - (- 3)

Add and subtract (left to right)

4 - (- 3) : 7

4 - (- 3)

Apply rule

- (- a) = + a

- (- 3) = + 3

= 4 + 3

4 + 3 = 7

= 7

= 7

4 + 4 \times 5 - 12 + 8 \div (4) (2) - 16

(22 - 3 + (\frac{4}{2}) - 1 + 9) \times 3

3 \times 36 \div 18 + 4 \times 9 - 80

- 5 + (- 3 - 2 - 1) + 3^{2}

3 (13 \div 12) - 2