What is 3+2/3 \times (-4) ?

The solution to 3+2/3 \times (-4) is 1/3

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3+2/3 \times (-4)

3 + \frac{2}{3} \cdot (- 4)

\frac{1}{3}

Solution steps

3 + \frac{2}{3} (- 4)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{2}{3} (- 4) : - \frac{8}{3}

\frac{2}{3} (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{2}{3} (- 4) = - \frac{2}{3} \cdot 4

Convert element to fraction:

4 = \frac{4}{1}

= - \frac{2}{3} \cdot \frac{4}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{2}{3} \cdot \frac{4}{1} = \frac{2 \cdot 4}{3 \cdot 1}

= - \frac{2 \cdot 4}{3 \cdot 1}

Multiply the numbers:

2 \cdot 4 = 8

= - \frac{8}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= - \frac{8}{3}

= 3 - \frac{8}{3}

Add and subtract (left to right)

3 - \frac{8}{3} : \frac{1}{3}

3 - \frac{8}{3}

3 - \frac{8}{3} = \frac{1}{3}

3 - \frac{8}{3}

Convert element to fraction:

3 = \frac{3 \cdot 3}{3}

= \frac{3 \cdot 3}{3} - \frac{8}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 \cdot 3 - 8}{3}

3 \cdot 3 - 8 = 1

3 \cdot 3 - 8

Multiply the numbers:

3 \cdot 3 = 9

= 9 - 8

Subtract the numbers:

9 - 8 = 1

= 1

= \frac{1}{3}

= \frac{1}{3}

= \frac{1}{3}

4 (14) + 7 + 7 (14) - 35

125 \times 5 - 25 + 10

- 1 + (- \frac{2}{5} \cdot 3)

2 \times 3 - 2 + 4 \times 2 + 3

1 1^{2} + 1 7^{2}