What is 4(-3)^2+3(-3) ?

The solution to 4(-3)^2+3(-3) is 27

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4(-3)^2+3(-3)

4 (- 3)^{2} + 3 (- 3)

27

Solution steps

4 (- 3)^{2} + 3 (- 3)

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 4 \cdot 9 + 3 (- 3)

Multiply and divide (left to right)

4 \cdot 9 : 36

4 \cdot 9

4 \cdot 9 = 36

= 36

= 36 + 3 (- 3)

Multiply and divide (left to right)

3 (- 3) : - 9

3 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 3) = - 3 \cdot 3 = - 9

= - 9

= 36 - 9

Add and subtract (left to right)

36 - 9 : 27

36 - 9

36 - 9 = 27

= 27

= 27

- 2^{3} - 3 (- 2)^{2}

16 \times 3 + 7 \div 7 - 13 \times 9

- 10 \cdot 1 2^{2}

(3 (- 20 + 8)) \div (1 - 2 \times 5)

- (- 2)^{2} - 4