What is 7+4+3^2-5(3)+2 ?

The solution to 7+4+3^2-5(3)+2 is 7

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7+4+3^2-5(3)+2

7 + 4 + 3^{2} - 5 (3) + 2

7

Solution steps

7 + 4 + 3^{2} - 5 (3) + 2

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 7 + 4 + 9 - 5 (3) + 2

Multiply and divide (left to right)

5 (3) : 15

5 (3)

Apply rule:

(a) = a

(3) = 3

= 5 \cdot 3

Multiply the numbers:

5 \cdot 3 = 15

= 15

= 7 + 4 + 9 - 15 + 2

Add and subtract (left to right)

7 + 4 + 9 - 15 + 2 : 7

7 + 4 + 9 - 15 + 2

7 + 4 = 11

= 11 + 9 - 15 + 2

11 + 9 = 20

= 20 - 15 + 2

20 - 15 = 5

= 5 + 2

5 + 2 = 7

= 7

= 7

3 \cdot 3^{3}

- 2^{2} + 5

1 - (- 3 - 2 + 8) + (2 + 3 + 1)

(4 + 3)^{2}

6^{5} + 1