What is -6-2 1/3 \div (-3/4) ?

The solution to -6-2 1/3 \div (-3/4) is -26/9

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-6-2 1/3 \div (-3/4)

- 6 - 2 \frac{1}{3} \div (- \frac{3}{4})

- \frac{26}{9}

Solution steps

- 6 - 2 \frac{1}{3} \div (- \frac{3}{4})

Convert mixed numbers to improper fractions:

2 \frac{1}{3} = \frac{7}{3}

2 \frac{1}{3}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{1}{3} = \frac{2 \cdot 3 + 1}{3}

= \frac{7}{3}

= - 6 - \frac{7}{3} \div (- \frac{3}{4})

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{7}{3} \div (- \frac{3}{4}) : - \frac{28}{9}

\frac{7}{3} \div (- \frac{3}{4})

Apply rule

a \div (- b) = - a \div b

\frac{7}{3} \div (- \frac{3}{4}) = - \frac{7}{3} \div \frac{3}{4}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= - \frac{7}{3} \cdot \frac{4}{3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{7 \cdot 4}{3 \cdot 3}

Multiply the numbers:

7 \cdot 4 = 28

= - \frac{28}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= - \frac{28}{9}

= - 6 - (- \frac{28}{9})

Add and subtract (left to right)

- 6 - (- \frac{28}{9}) : - \frac{26}{9}

- 6 - (- \frac{28}{9})

Apply rule

- (- a) = + a

- (- \frac{28}{9}) = + \frac{28}{9}

= - 6 + \frac{28}{9}

- 6 + \frac{28}{9} = - \frac{26}{9}

= - \frac{26}{9}

= - \frac{26}{9}

4 (5^{2} - 3^{3})^{0}

9 - 15 + 2

(65 \frac{5}{11} - 64) \times 16

5 + (- 3) - (- 2) + (4 - 6) - [3 - (6 - 4)]

36 - (- 9)^{2}