What is -4(8\div (-11+17)+3(-2+6)) ?

The solution to -4(8\div (-11+17)+3(-2+6)) is -160/3

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-4(8\div (-11+17)+3(-2+6))

- 4 (8 \div (- 11 + 17) + 3 (- 2 + 6))

- \frac{160}{3}

Solution steps

- 4 (8 \div (- 11 + 17) + 3 (- 2 + 6))

Follow the PEMDAS order of operations

Calculate within parentheses

(8 \div (- 11 + 17) + 3 (- 2 + 6)) : \frac{40}{3}

8 \div (- 11 + 17) + 3 (- 2 + 6)

Calculate within parentheses

(- 11 + 17) : 6

- 11 + 17

- 11 + 17 = 6

= 6

= 8 \div 6 + 3 (- 2 + 6)

Calculate within parentheses

(- 2 + 6) : 4

- 2 + 6

- 2 + 6 = 4

= 4

= 8 \div 6 + 3 \cdot 4

Multiply and divide (left to right)

8 \div 6 : \frac{8}{6}

8 \div 6

8 \div 6 = \frac{8}{6}

= \frac{8}{6}

= \frac{8}{6} + 3 \cdot 4

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= \frac{8}{6} + 12

Add and subtract (left to right)

\frac{8}{6} + 12 : \frac{40}{3}

\frac{8}{6} + 12

\frac{8}{6} + 12 = \frac{40}{3}

\frac{8}{6} + 12

Cancel

\frac{8}{6} : \frac{4}{3}

\frac{8}{6}

Cancel the common factor:

2

= \frac{4}{3}

= \frac{4}{3} + 12

Convert element to fraction:

12 = \frac{12 \cdot 3}{3}

= \frac{12 \cdot 3}{3} + \frac{4}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{12 \cdot 3 + 4}{3}

12 \cdot 3 + 4 = 40

12 \cdot 3 + 4

Multiply the numbers:

12 \cdot 3 = 36

= 36 + 4

Add the numbers:

36 + 4 = 40

= 40

= \frac{40}{3}

= \frac{40}{3}

= \frac{40}{3}

= - 4 \cdot \frac{40}{3}

Multiply and divide (left to right)

- 4 \cdot \frac{40}{3} : - \frac{160}{3}

- 4 \cdot \frac{40}{3}

Convert element to fraction:

4 = \frac{4}{1}

= - \frac{4}{1} \cdot \frac{40}{3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{4}{1} \cdot \frac{40}{3} = \frac{4 \cdot 40}{1 \cdot 3}

= - \frac{4 \cdot 40}{1 \cdot 3}

Multiply the numbers:

4 \cdot 40 = 160

= - \frac{160}{1 \cdot 3}

Multiply the numbers:

1 \cdot 3 = 3

= - \frac{160}{3}

= - \frac{160}{3}

3^{3} - 3^{3}

252 + 2^{9} - 126

1 9^{2} + 1 6^{2}

- (- 2 (2)^{3} + 2)

3^{3} - 3^{4}

What is -4(8\div (-11+17)+3(-2+6)) ?
The solution to -4(8\div (-11+17)+3(-2+6)) is -160/3