What is 9\times (12/3)^2 ?

The solution to 9\times (12/3)^2 is 144

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9\times (12/3)^2

9 \cdot (\frac{12}{3})^{2}

144

Solution steps

9 (\frac{12}{3})^{2}

\frac{12}{3} = 4

Divide the numbers:

\frac{12}{3} = 4

4

= 9 \cdot 4^{2}

Follow the PEMDAS order of operations

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 9 \cdot 16

Multiply and divide (left to right)

9 \cdot 16 : 144

9 \cdot 16

9 \cdot 16 = 144

= 144

= 144

(3 - 5)^{5}

180 (11 - 2)

(\frac{1}{2} + 2) (- 2) + \frac{9}{2}

2^{1} + 2^{2} + 2^{3}

3 \div 3^{5}