What is (-3)^2+(-1^{20})+(-2)^0-(-3^2) ?

The solution to (-3)^2+(-1^{20})+(-2)^0-(-3^2) is 18

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(-3)^2+(-1^{20})+(-2)^0-(-3^2)

(- 3)^{2} + (- 1^{20}) + (- 2)^{0} - (- 3^{2})

18

Solution steps

(- 3)^{2} + (- 1^{20}) + (- 2)^{0} - (- 3^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(- 1^{20}) : - 1

- 1^{20}

- 1^{20} = - 1

= - 1

= (- 3)^{2} - 1 + (- 2)^{0} - (- 3^{2})

Calculate within parentheses

(- 3^{2}) : - 9

- 3^{2}

- 3^{2} = - 9

= - 9

= (- 3)^{2} - 1 + (- 2)^{0} - (- 3^{2})

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 9 - 1 + (- 2)^{0} - (- 3^{2})

Calculate exponents

(- 2)^{0} : 1

(- 2)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{0} = 2^{0} = 1

= 1

= 9 - 1 + 1 - (- 3^{2})

Add and subtract (left to right)

9 - 1 + 1 - (- 3^{2}) : 18

9 - 1 + 1 - (- 3^{2})

9 - 1 = 8

= 8 + 1 - (- 3^{2})

8 + 1 = 9

= 9 - (- 3^{2})

Apply rule

- (- a) = + a

- (- 3^{2}) = + 3^{2}

= 9 + 3^{2}

9 + 3^{2} = 18

= 18

= 18

(- 3)^{2} + (- 3)^{3}

6^{3} + 6^{4}

- 2 (- 4 + 3)^{2} - 1

18 - 2 \times 8

- 1 - 2 (- 2)

What is (-3)^2+(-1^{20})+(-2)^0-(-3^2) ?
The solution to (-3)^2+(-1^{20})+(-2)^0-(-3^2) is 18