What is 51-6(2)-14\div 7-5 ?

The solution to 51-6(2)-14\div 7-5 is 32

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51-6(2)-14\div 7-5

51 - 6 (2) - 14 \div 7 - 5

32

Solution steps

51 - 6 (2) - 14 \div 7 - 5

Follow the PEMDAS order of operations

Multiply and divide (left to right)

6 (2) : 12

6 (2)

Apply rule:

(a) = a

(2) = 2

= 6 \cdot 2

Multiply the numbers:

6 \cdot 2 = 12

= 12

= 51 - 12 - 14 \div 7 - 5

Multiply and divide (left to right)

14 \div 7 : 2

14 \div 7

14 \div 7 = 2

= 2

= 51 - 12 - 2 - 5

Add and subtract (left to right)

51 - 12 - 2 - 5 : 32

51 - 12 - 2 - 5

51 - 12 = 39

= 39 - 2 - 5

39 - 2 = 37

= 37 - 5

37 - 5 = 32

= 32

= 32

6^{0} - 6 \times 2^{2} + 6

\frac{5 ^{4} \cdot 5}{5 ^{7}}

6 + 2 \cdot 5^{2}

6^{2} \div 3 + 5 (3 + 4) \times 2 - 9^{0} + 1^{8}

8 - 3 [2 - 4 (- 2 - 2) + 3 - 5 (- 1 + 3) + 1] - 5