What is 4(2-6)+1/2-3/2 ?

The solution to 4(2-6)+1/2-3/2 is -17

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4(2-6)+1/2-3/2

4 (2 - 6) + \frac{1}{2} - \frac{3}{2}

- 17

Solution steps

4 (2 - 6) + \frac{1}{2} - \frac{3}{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(2 - 6) : - 4

2 - 6

2 - 6 = - 4

= - 4

= 4 (- 4) + \frac{1}{2} - \frac{3}{2}

Multiply and divide (left to right)

4 (- 4) : - 16

4 (- 4)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 4) = - 4 \cdot 4 = - 16

= - 16

= - 16 + \frac{1}{2} - \frac{3}{2}

Add and subtract (left to right)

- 16 + \frac{1}{2} - \frac{3}{2} : - 17

- 16 + \frac{1}{2} - \frac{3}{2}

- 16 + \frac{1}{2} = - \frac{31}{2}

= - \frac{31}{2} - \frac{3}{2}

- \frac{31}{2} - \frac{3}{2} = - 17

- \frac{31}{2} - \frac{3}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 31 - 3}{2}

Subtract the numbers:

- 31 - 3 = - 34

= \frac{- 34}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{34}{2}

Divide the numbers:

\frac{34}{2} = 17

= - 17

= - 17

= - 17

- (38 - 47)^{2} + 3209

3 \frac{1}{2} \div 10 + 1 \frac{1}{5}

2 (5 - 3) + (5 + 6)

7^{5} - 7^{3}

- [3 - (2 - (- 3))] - [4 - (- 5 - (2 - 5) - 2)]