What is 3^2-3(3)(-1)+5(-1)^2 ?

The solution to 3^2-3(3)(-1)+5(-1)^2 is 23

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3^2-3(3)(-1)+5(-1)^2

3^{2} - 3 (3) (- 1) + 5 (- 1)^{2}

23

Solution steps

3^{2} - 3 (3) (- 1) + 5 (- 1)^{2}

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 3 (3) (- 1) + 5 (- 1)^{2}

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 9 - 3 (3) (- 1) + 5 \cdot 1

Multiply and divide (left to right)

3 (3) (- 1) : - 9

3 (3) (- 1)

3 (3) = 9

3 (3)

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= 9 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

9 (- 1) = - 9 \cdot 1 = - 9

= - 9

= 9 - (- 9) + 5 \cdot 1

Multiply and divide (left to right)

5 \cdot 1 : 5

5 \cdot 1

5 \cdot 1 = 5

= 5

= 9 - (- 9) + 5

Add and subtract (left to right)

9 - (- 9) + 5 : 23

9 - (- 9) + 5

Apply rule

- (- a) = + a

- (- 9) = + 9

= 9 + 9 + 5

9 + 9 = 18

= 18 + 5

18 + 5 = 23

= 23

= 23

2^{7} + 2^{6} + 2^{5} + 2^{4} + 2^{3} + 2^{2} + 2 + 1

4 + 3^{2} \cdot 2

2^{10} + 1

\frac{4}{4 ^{2} + 16}

- 9^{0} + 9^{0}