What is -(3)^2+6(3)-8 ?

The solution to -(3)^2+6(3)-8 is 1

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-(3)^2+6(3)-8

- (3)^{2} + 6 (3) - 8

1

Solution steps

- (3)^{2} + 6 (3) - 8

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= - 9 + 6 (3) - 8

Multiply and divide (left to right)

6 (3) : 18

6 (3)

Apply rule:

(a) = a

(3) = 3

= 6 \cdot 3

Multiply the numbers:

6 \cdot 3 = 18

= 18

= - 9 + 18 - 8

Add and subtract (left to right)

- 9 + 18 - 8 : 1

- 9 + 18 - 8

- 9 + 18 = 9

= 9 - 8

9 - 8 = 1

= 1

= 1

(1)^{3} - 4 (1)^{2} + 5 (1) - 3

(- 3) \times (+ 4) \times (- 7)

63 \div 7 \times (30 - 27)

83 - (9 - 2)^{2}

4 \times 6 \div 3 + 15