What is 3 4/3+1(1/3)+418/3 ?

The solution to 3 4/3+1(1/3)+418/3 is 144

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3 4/3+1(1/3)+418/3

3 \frac{4}{3} + 1 (\frac{1}{3}) + 418/3

144

Solution steps

3 \frac{4}{3} + 1 (\frac{1}{3}) + 418/3

Convert mixed numbers to improper fractions:

3 \frac{4}{3} = \frac{13}{3}

3 \frac{4}{3}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

3 \frac{4}{3} = \frac{3 \cdot 3 + 4}{3}

= \frac{13}{3}

= \frac{13}{3} + 1 (\frac{1}{3}) + 418/3

Follow the PEMDAS order of operations

Multiply and divide (left to right)

1 \cdot (\frac{1}{3}) : \frac{1}{3}

1 \cdot (\frac{1}{3})

Apply rule:

(a) = a

(\frac{1}{3}) = \frac{1}{3}

= 1 \cdot \frac{1}{3}

Multiply the numbers:

1 \cdot \frac{1}{3} = \frac{1}{3}

= \frac{1}{3}

= \frac{13}{3} + \frac{1}{3} + 418/3

Multiply and divide (left to right)

418/3 : \frac{418}{3}

418/3

418/3 = \frac{418}{3}

= \frac{418}{3}

= \frac{13}{3} + \frac{1}{3} + \frac{418}{3}

Add and subtract (left to right)

\frac{13}{3} + \frac{1}{3} + \frac{418}{3} : 144

\frac{13}{3} + \frac{1}{3} + \frac{418}{3}

\frac{13}{3} + \frac{1}{3} = \frac{14}{3}

\frac{13}{3} + \frac{1}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{13 + 1}{3}

Add the numbers:

13 + 1 = 14

= \frac{14}{3}

= \frac{14}{3} + \frac{418}{3}

\frac{14}{3} + \frac{418}{3} = 144

\frac{14}{3} + \frac{418}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{14 + 418}{3}

Add the numbers:

14 + 418 = 432

= \frac{432}{3}

Divide the numbers:

\frac{432}{3} = 144

= 144

= 144

= 144

((6) - 3)^{2}

5 (4 - 2) + 4 \cdot 2

2 - \frac{3}{4} - \frac{1}{2}

7 - [2 \cdot 9 (4 + 13) + 4 \div 2]

18 (2)^{2}