What is 4(3^2)(2^2)+5(3)(2)+7 ?

The solution to 4(3^2)(2^2)+5(3)(2)+7 is 181

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4(3^2)(2^2)+5(3)(2)+7

4 (3^{2}) (2^{2}) + 5 (3) (2) + 7

181

Solution steps

4 (3^{2}) (2^{2}) + 5 (3) (2) + 7

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{2}) : 9

3^{2}

3^{2} = 9

= 9

= 4 \cdot 9 (2^{2}) + 5 (3) (2) + 7

Calculate within parentheses

(2^{2}) : 4

2^{2}

2^{2} = 4

= 4

= 4 \cdot 9 \cdot 4 + 5 (3) (2) + 7

Multiply and divide (left to right)

4 \cdot 9 \cdot 4 : 144

4 \cdot 9 \cdot 4

4 \cdot 9 = 36

= 36 \cdot 4

36 \cdot 4 = 144

= 144

= 144 + 5 (3) (2) + 7

Multiply and divide (left to right)

5 (3) (2) : 30

5 (3) (2)

5 (3) = 15

5 (3)

Apply rule:

(a) = a

(3) = 3

= 5 \cdot 3

Multiply the numbers:

5 \cdot 3 = 15

= 15

= 15 (2)

15 (2) = 30

15 (2)

Apply rule:

(a) = a

(2) = 2

= 15 \cdot 2

Multiply the numbers:

15 \cdot 2 = 30

= 30

= 30

= 144 + 30 + 7

Add and subtract (left to right)

144 + 30 + 7 : 181

144 + 30 + 7

144 + 30 = 174

= 174 + 7

174 + 7 = 181

= 181

= 181

(4)^{2} - 4 (4)

8 + 18 - 15 - 12 - 15 - 5 - 8

- 2 (2 - 4)^{2} + 3

5 - 2 \times 3

8 - 6 \div (- 3) + 4 \cdot (- 2) + 5 \cdot (- 10)