What is 11-3(39\div 22) ?

The solution to 11-3(39\div 22) is 5 15/22

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Popular >

11-3(39\div 22)

Solution

11 - 3 (39 \div 22)

Solution

5 \frac{15}{22}

Solution steps

11 - 3 (39 \div 22)

Follow the PEMDAS order of operations

Calculate within parentheses

(39 \div 22) : \frac{39}{22}

39 \div 22

39 \div 22 = \frac{39}{22}

= \frac{39}{22}

= 11 - 3 \cdot \frac{39}{22}

Multiply and divide (left to right)

3 \cdot \frac{39}{22} : \frac{117}{22}

3 \cdot \frac{39}{22}

Convert element to fraction:

3 = \frac{3}{1}

= \frac{3}{1} \cdot \frac{39}{22}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 39}{1 \cdot 22}

Multiply the numbers:

3 \cdot 39 = 117

= \frac{117}{1 \cdot 22}

Multiply the numbers:

1 \cdot 22 = 22

= \frac{117}{22}

= 11 - \frac{117}{22}

Add and subtract (left to right)

11 - \frac{117}{22} : \frac{125}{22}

11 - \frac{117}{22}

11 - \frac{117}{22} = \frac{125}{22}

11 - \frac{117}{22}

Convert element to fraction:

11 = \frac{11 \cdot 22}{22}

= \frac{11 \cdot 22}{22} - \frac{117}{22}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{11 \cdot 22 - 117}{22}

11 \cdot 22 - 117 = 125

11 \cdot 22 - 117

Multiply the numbers:

11 \cdot 22 = 242

= 242 - 117

Subtract the numbers:

242 - 117 = 125

= 125

= \frac{125}{22}

= \frac{125}{22}

= \frac{125}{22}

Convert improper fractions to mixed numbers:

\frac{125}{22} = 5 \frac{15}{22}

\frac{125}{22} = 5

Remainder

15

\frac{125}{22}

Write the problem in long division format

22 \overline{∣ 125}

Divide

125

22

to get

5

Divide

125

22

to get

5

5 22 \overline{∣ 125}

Multiply the quotient digit

(5)

by the divisor

22

5 22 \overline{∣ 125} \underline{110}

Subtract

110

from

125

5 22 \overline{∣ 125} \underline{110} 15

5 22 \overline{∣ 125} \underline{110} 15

The solution for Long Division of

\frac{125}{22}

5

with remainder of

15

5 Remainder 15

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{125}{22} = 5 \frac{15}{22}

= 5 \frac{15}{22}

= 5 \frac{15}{22}

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Frequently Asked Questions (FAQ)

What is 11-3(39\div 22) ?
The solution to 11-3(39\div 22) is 5 15/22