What is (-6)^3\div 3^2\div [-9-(-8)]^3 ?

The solution to (-6)^3\div 3^2\div [-9-(-8)]^3 is 24

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(-6)^3\div 3^2\div [-9-(-8)]^3

(- 6)^{3} \div 3^{2} \div [- 9 - (- 8)]^{3}

24

Solution steps

(- 6)^{3} \div 3^{2} \div [- 9 - (- 8)]^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

[- 9 - (- 8)] : - 1

- 9 - (- 8)

Add and subtract (left to right)

Apply rule

- (- a) = + a

- (- 8) = + 8

= - 9 + 8

- 9 + 8 = - 1

= - 1

= (- 6)^{3} \div 3^{2} \div (- 1)^{3}

Calculate exponents

(- 6)^{3} : - 216

(- 6)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 6)^{3} = - 6^{3} = - 216

= - 216

= - 216 \div 3^{2} \div (- 1)^{3}

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= - 216 \div 9 \div (- 1)^{3}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 216 \div 9 \div (- 1)

Multiply and divide (left to right)

- 216 \div 9 \div (- 1) : 24

- 216 \div 9 \div (- 1)

- 216 \div 9 = - 24

= - 24 \div (- 1)

Apply rule

- a \div (- b) = a \div b

- 24 \div (- 1) = 24 \div 1 = 24

= 24

= 24

5 \cdot 1 0^{3} + 6 \cdot 1 0^{2}

13 - 12 + 5 - 56

(\frac{1}{2} + \frac{1}{3}) \div \frac{1}{5}

288030 \div 13000 - 240000 \div 13000

2 (5)^{2} - 12 (5) + 20

What is (-6)^3\div 3^2\div [-9-(-8)]^3 ?
The solution to (-6)^3\div 3^2\div [-9-(-8)]^3 is 24