What is 2*[(2*5-30\div 2-3*2)\div 4+1] ?

The solution to 2*[(2*5-30\div 2-3*2)\div 4+1] is -7/2

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Popular >

2[(25-30\div 2-3*2)\div 4+1]

Solution

2 \cdot [(2 \cdot 5 - 30 \div 2 - 3 \cdot 2) \div 4 + 1]

Solution

- \frac{7}{2}

Solution steps

2 [(2 \cdot 5 - 30 \div 2 - 3 \cdot 2) \div 4 + 1]

Follow the PEMDAS order of operations

Calculate within parentheses

[(2 \cdot 5 - 30 \div 2 - 3 \cdot 2) \div 4 + 1] : - \frac{7}{4}

(2 \cdot 5 - 30 \div 2 - 3 \cdot 2) \div 4 + 1

Calculate within parentheses

(2 \cdot 5 - 30 \div 2 - 3 \cdot 2) : - 11

2 \cdot 5 - 30 \div 2 - 3 \cdot 2

Multiply and divide (left to right)

2 \cdot 5 : 10

2 \cdot 5

2 \cdot 5 = 10

= 10

= 10 - 30 \div 2 - 3 \cdot 2

Multiply and divide (left to right)

30 \div 2 : 15

30 \div 2

30 \div 2 = 15

= 15

= 10 - 15 - 3 \cdot 2

Multiply and divide (left to right)

3 \cdot 2 : 6

3 \cdot 2

3 \cdot 2 = 6

= 6

= 10 - 15 - 6

Add and subtract (left to right)

10 - 15 - 6 : - 11

10 - 15 - 6

10 - 15 = - 5

= - 5 - 6

- 5 - 6 = - 11

= - 11

= - 11

= - 11 \div 4 + 1

Multiply and divide (left to right)

- 11 \div 4 : \frac{- 11}{4}

- 11 \div 4

- 11 \div 4 = \frac{- 11}{4}

= \frac{- 11}{4}

= \frac{- 11}{4} + 1

Add and subtract (left to right)

\frac{- 11}{4} + 1 : - \frac{7}{4}

\frac{- 11}{4} + 1

\frac{- 11}{4} + 1 = - \frac{7}{4}

\frac{- 11}{4} + 1

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{11}{4} + 1

Convert element to fraction:

1 = \frac{1 \cdot 4}{4}

= \frac{1 \cdot 4}{4} - \frac{11}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 4 - 11}{4}

1 \cdot 4 - 11 = - 7

1 \cdot 4 - 11

Multiply the numbers:

1 \cdot 4 = 4

= 4 - 11

Subtract the numbers:

4 - 11 = - 7

= - 7

= \frac{- 7}{4}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{7}{4}

= - \frac{7}{4}

= - \frac{7}{4}

= 2 (- \frac{7}{4})

Multiply and divide (left to right)

2 (- \frac{7}{4}) : - \frac{7}{2}

2 (- \frac{7}{4})

Apply rule

a \cdot (- b) = - a \cdot b

2 (- \frac{7}{4}) = - 2 \cdot \frac{7}{4}

Convert element to fraction:

2 = \frac{2}{1}

= - \frac{2}{1} \cdot \frac{7}{4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{2}{1} \cdot \frac{7}{4} = \frac{2 \cdot 7}{1 \cdot 4}

= - \frac{2 \cdot 7}{1 \cdot 4}

\frac{2 \cdot 7}{1 \cdot 4} = \frac{7}{2}

\frac{2 \cdot 7}{1 \cdot 4}

Multiply the numbers:

1 \cdot 4 = 4

= \frac{2 \cdot 7}{4}

Factor the number:

4 = 2 \cdot 2

= \frac{2 \cdot 7}{2 \cdot 2}

Cancel the common factor:

2

= \frac{7}{2}

= - \frac{7}{2}

= - \frac{7}{2}

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5^{2} \cdot 40 \div (- 15 + 17)^{2}

4(5-(6+(2-4)^2\div 2+8))

4 (5 - (6 + (2 - 4)^{2} \div 2 + 8))

4+12\div 2-3

4 + 12 \div 2 - 3

-1+1-1+1

- 1 + 1 - 1 + 1

2\div 3\div 4\div 5\div 6\div 8

2 \div 3 \div 4 \div 5 \div 6 \div 8

Frequently Asked Questions (FAQ)

What is 2*[(2*5-30\div 2-3*2)\div 4+1] ?
The solution to 2*[(2*5-30\div 2-3*2)\div 4+1] is -7/2