What is (2(-1)^2+1)(3(2)-1) ?

The solution to (2(-1)^2+1)(3(2)-1) is 15

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(2(-1)^2+1)(3(2)-1)

(2 (- 1)^{2} + 1) (3 (2) - 1)

15

Solution steps

(2 (- 1)^{2} + 1) (3 (2) - 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(2 (- 1)^{2} + 1) : 3

2 (- 1)^{2} + 1

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 2 \cdot 1 + 1

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2 + 1

Add and subtract (left to right)

2 + 1 : 3

2 + 1

2 + 1 = 3

= 3

= 3

= 3 (3 (2) - 1)

Calculate within parentheses

(3 (2) - 1) : 5

3 (2) - 1

Multiply and divide (left to right)

3 (2) : 6

3 (2)

Apply rule:

(a) = a

(2) = 2

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

= 6 - 1

Add and subtract (left to right)

6 - 1 : 5

6 - 1

6 - 1 = 5

= 5

= 5

= 3 \cdot 5

Multiply and divide (left to right)

3 \cdot 5 : 15

3 \cdot 5

3 \cdot 5 = 15

= 15

= 15

- 3 (- 2 + (- 3^{2}))

\frac{1}{3 ( 11 ) ^{3}}

(2^{2} + 4^{2} + 3^{3}) \cdot 2^{2}

- \frac{3}{2} (2) + 1

- \frac{3}{2} (2) + 4