What is 2/27 (3^7-8*7+2) ?

The solution to 2/27 (3^7-8*7+2) is 158

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2/27 (3^7-8*7+2)

\frac{2}{27} (3^{7} - 8 \cdot 7 + 2)

158

Solution steps

\frac{2}{27} (3^{7} - 8 \cdot 7 + 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(3^{7} - 8 \cdot 7 + 2) : 2133

3^{7} - 8 \cdot 7 + 2

Calculate exponents

3^{7} : 2187

3^{7}

3^{7} = 2187

= 2187

= 2187 - 8 \cdot 7 + 2

Multiply and divide (left to right)

8 \cdot 7 : 56

8 \cdot 7

8 \cdot 7 = 56

= 56

= 2187 - 56 + 2

Add and subtract (left to right)

2187 - 56 + 2 : 2133

2187 - 56 + 2

2187 - 56 = 2131

= 2131 + 2

2131 + 2 = 2133

= 2133

= 2133

= \frac{2}{27} \cdot 2133

Multiply and divide (left to right)

\frac{2}{27} \cdot 2133 : 158

\frac{2}{27} \cdot 2133

Convert element to fraction:

2133 = \frac{2133}{1}

= \frac{2}{27} \cdot \frac{2133}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 2133}{27 \cdot 1}

Cancel

\frac{2 \cdot 2133}{27 \cdot 1} : 158

\frac{2 \cdot 2133}{27 \cdot 1}

Multiply the numbers:

27 \cdot 1 = 27

= \frac{2 \cdot 2133}{27}

Divide the numbers:

\frac{2133}{27} = 79

= 2 \cdot 79

Multiply the numbers:

2 \cdot 79 = 158

= 158

= 158

= 158

16 + (- 18) - 24 + 45

2^{4} \cdot 5

2^{2} - 2 (2) - 8

- 2^{2} + 8 + 5

2 (5)^{2} - 5 - 1