leitkurve x=(4/5-3y)*(4/5+3y)

Lösung

leitkurve

x = (\frac{4}{5} - 3 y) \cdot (\frac{4}{5} + 3 y)

x = \frac{601}{900}

Schritte zur Lösung

Rewrite

x = (\frac{4}{5} - 3 y) (\frac{4}{5} + 3 y)

in the standard form

4 (- \frac{1}{36}) (x - \frac{16}{25}) = (y - 0)^{2}

(h, k) = (\frac{16}{25}, 0), p = - \frac{1}{36}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(\frac{16}{25}, 0)

x-coordinate

x = \frac{16}{25} - p

x = \frac{16}{25} - (- \frac{1}{36})

Fasse zusammen

x = \frac{601}{900}

d i rec t r i x y = (6 x - 1) (3 x - 2)

d i rec t r i x y = \frac{x ^{2}}{32}

d i rec t r i x 3 y^{2} - 4 x - 6 y + 23 = 0

d i rec t r i x x^{2} + 4 x - 5

d i rec t r i x x = \frac{- 1}{4} (y + 2)^{2}