leitkurve-0.0000848x^2-0.006005x+1.004

Lösung

leitkurve

- 0.0000848 x^{2} - 0.006005 x + 1.004

y = 2948.11320 \dots

Schritte zur Lösung

Rewrite

y = - 0.0000848 x^{2} - 0.006005 x + 1.004

in the standard form

4 (- 2948.11320 \dots) (y - 0) = (x - (- \frac{0.006005}{0.0001696}))^{2}

(h, k) = (- \frac{0.006005}{0.0001696}, 0), p = - 2948.11320 \dots

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{0.006005}{0.0001696}, 0)

y-coordinate

y = 0 - p

y = 0 - (- 2948.11320 \dots)

Fasse zusammen

y = 2948.11320 \dots

d i rec t r i x y = x^{2} - 3 x - 4

d i rec t r i x - 2 x^{2} + 4

d i rec t r i x (x - 2)^{2} = - 4 (y - 2)

d i rec t r i x 9 x^{2} - 4

d i rec t r i x y = - (x - 4)^{2} + 1