leitkurve y=-2x^2+5x-6

Lösung

leitkurve

y = - 2 x^{2} + 5 x - 6

y = - \frac{11}{4}

Schritte zur Lösung

Rewrite

y = - 2 x^{2} + 5 x - 6

in the standard form

4 (- \frac{1}{8}) (y - (- \frac{23}{8})) = (x - \frac{5}{4})^{2}

(h, k) = (\frac{5}{4}, - \frac{23}{8}), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(\frac{5}{4}, - \frac{23}{8})

y-coordinate

y = - \frac{23}{8} - p

y = - \frac{23}{8} - (- \frac{1}{8})

Fasse zusammen

y = - \frac{11}{4}

d i rec t r i x y^{2} + 2 x = 0

d i rec t r i x y = - (0.009 (x - 220)^{2} - 220)

d i rec t r i x y = x^{2} - 10 x - 24

d i rec t r i x y = x^{2} + 2 x - 12

d i rec t r i x y = 4 (x - 1)^{2} - 2