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Beliebt Geometry >

leitkurve x=(2y+5)^2

Lösung

leitkurve

x = (2 y + 5)^{2}

Lösung

x = - \frac{1}{16}

Schritte zur Lösung

Rewrite

x = (2 y + 5)^{2}

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - (- \frac{5}{2}))^{2}

(h, k) = (0, - \frac{5}{2}), p = \frac{1}{16}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, - \frac{5}{2})

x-coordinate

x = 0 - p

x = 0 - \frac{1}{16}

Fasse zusammen

x = - \frac{1}{16}

Graph

Beliebte Beispiele

leitkurve 6x^2-12x

d i rec t r i x 6 x^{2} - 12 x

leitkurve t^2+2

d i rec t r i x t^{2} + 2

leitkurve-1/2 (x-4)^2+3

d i rec t r i x - \frac{1}{2} (x - 4)^{2} + 3

leitkurve-4x^2+8x+1

d i rec t r i x - 4 x^{2} + 8 x + 1

leitkurve x-4y^2=0

d i rec t r i x x - 4 y^{2} = 0