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Beliebt Geometry >

leitkurve y^2-10x+4y-16=0

Lösung

leitkurve

y^{2} - 10 x + 4 y - 16 = 0

Lösung

x = - \frac{9}{2}

Schritte zur Lösung

Rewrite

y^{2} - 10 x + 4 y - 16 = 0

in the standard form

4 \cdot \frac{5}{2} (x - (- 2)) = (y - (- 2))^{2}

(h, k) = (- 2, - 2), p = \frac{5}{2}

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(- 2, - 2)

x-coordinate

x = - 2 - p

x = - 2 - \frac{5}{2}

Fasse zusammen

x = - \frac{9}{2}

Graph

Beliebte Beispiele

leitkurve-4x^2+6x-1

d i rec t r i x - 4 x^{2} + 6 x - 1

leitkurve y=-2x^2+8x

d i rec t r i x y = - 2 x^{2} + 8 x

leitkurve y=-4x^2-4

d i rec t r i x y = - 4 x^{2} - 4

leitkurve (x-4)^2=-8(y+3)

d i rec t r i x (x - 4)^{2} = - 8 (y + 3)

leitkurve y^2+33=-8x-23

d i rec t r i x y^{2} + 33 = - 8 x - 23