de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

leitkurve x^2=16y

Lösung

leitkurve

x^{2} = 16 y

Lösung

y = - 4

Schritte zur Lösung

Rewrite

x^{2} = 16 y

in the standard form:

4 \cdot 4 (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = 4

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - 4

Fasse zusammen

y = - 4

Graph

Beliebte Beispiele

scheitelpunkte f(x)=-x^2+6x+7

v er t i ces f (x) = - x^{2} + 6 x + 7

-(x^2)/(a^2)+(y^2)/(b^2)=1

- \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

asymptoten (x^2}{16}-\frac{y^2)/4 =1

a sy m pt o t es \frac{x ^{2}}{16} - \frac{y ^{2}}{4} = 1

-1/3 (x-3)=(y+5)^2

- \frac{1}{3} (x - 3) = (y + 5)^{2}

solvefor y,x^2-y^2=0

so l v e f or y, x^{2} - y^{2} = 0