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Beliebt Geometry >

leitkurve y=4x^2-24x+31

Lösung

leitkurve

y = 4 x^{2} - 24 x + 31

Lösung

y = - \frac{81}{16}

Schritte zur Lösung

Rewrite

y = 4 x^{2} - 24 x + 31

in the standard form

4 \cdot \frac{1}{16} (y - (- 5)) = (x - 3)^{2}

(h, k) = (3, - 5), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(3, - 5)

y-coordinate

y = - 5 - p

y = - 5 - \frac{1}{16}

Fasse zusammen

y = - \frac{81}{16}

Graph

Beliebte Beispiele

leitkurve y=-x^2+4x

d i rec t r i x y = - x^{2} + 4 x

leitkurve y^2+4x-14y=-53

d i rec t r i x y^{2} + 4 x - 14 y = - 53

leitkurve y=6x^2+12x

d i rec t r i x y = 6 x^{2} + 12 x

leitkurve y=-4(x-2)^2+16

d i rec t r i x y = - 4 (x - 2)^{2} + 16

leitkurve y^2-4y-8x-12=0

d i rec t r i x y^{2} - 4 y - 8 x - 12 = 0