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Beliebt Geometry >

foki 5x^2-3x+6

Lösung

foki

5 x^{2} - 3 x + 6

Lösung

(\frac{3}{10}, \frac{28}{5})

Schritte zur Lösung

Rewrite

y = 5 x^{2} - 3 x + 6

in the standard form

4 \cdot \frac{1}{20} (y - \frac{111}{20}) = (x - \frac{3}{10})^{2}

(h, k) = (\frac{3}{10}, \frac{111}{20}), p = \frac{1}{20}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{3}{10}, \frac{111}{20})

along the y-axis

(\frac{3}{10}, \frac{111}{20} + p)

= (\frac{3}{10}, \frac{111}{20} + \frac{1}{20})

Fasse zusammen

(\frac{3}{10}, \frac{28}{5})

Graph

Beliebte Beispiele

foki 2(y-4)=-1/4 (x-3)^2

f oc i 2 (y - 4) = - \frac{1}{4} (x - 3)^{2}

f oc i y \geq x^{2}

f oc i x^{2} + 4 x - 1

foki (x+5)^2=4(y-1)

f oc i (x + 5)^{2} = 4 (y - 1)

foki (x-5)^2-2(y+2)=0

f oc i (x - 5)^{2} - 2 (y + 2) = 0