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Beliebt Geometry >

foki+(2h^3+4h^2+5h)/h

Lösung

foki

+ \frac{2 h ^{3} + 4 h ^{2} + 5 h}{h}

Lösung

(- 1, \frac{25}{8})

Schritte zur Lösung

Rewrite

y = \frac{2 h ^{3} + 4 h ^{2} + 5 h}{h}

in the standard form

4 \cdot \frac{1}{8} (y - 3) = (h - (- 1))^{2}

(h, k) = (- 1, 3), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 1, 3)

along the y-axis

(- 1, 3 + p)

= (- 1, 3 + \frac{1}{8})

Fasse zusammen

(- 1, \frac{25}{8})

Graph

Beliebte Beispiele

foki y^2+20x+8y+56=0

f oc i y^{2} + 20 x + 8 y + 56 = 0

f oc i x^{2} = 3 y

foki (y-4)^2=-8(x-1)

f oc i (y - 4)^{2} = - 8 (x - 1)

foki (y-1)^2=16(x+3)

f oc i (y - 1)^{2} = 16 (x + 3)

foki y=-3x^2+12x-8

f oc i y = - 3 x^{2} + 12 x - 8