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Beliebt Geometry >

leitkurve y= 1/2 x^2

Lösung

leitkurve

y = \frac{1}{2} x^{2}

Lösung

y = - \frac{1}{2}

Schritte zur Lösung

Rewrite

y = \frac{1}{2} x^{2}

in the standard form:

4 \cdot \frac{1}{2} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{2}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{2}

Fasse zusammen

y = - \frac{1}{2}

Graph

Beliebte Beispiele

foki (y^2)/9-(x^2)/4 =1

f oc i \frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1

x^{2} = 3 y

(a+1)/b =(a-1)/b+(b+1)/a

\frac{a + 1}{b} = \frac{a - 1}{b} + \frac{b + 1}{a}

foki (x^2)/4+(y^2)/9 =1

f oc i \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

leitkurve y^2-y-x+1=0

d i rec t r i x y^{2} - y - x + 1 = 0