(x+92)^2+(y+54)^2=73

解答

(x + 92)^{2} + (y + 54)^{2} = 73

(a, b) = (- 92, - 54), r = 73

求解步骤

(x + 92)^{2} + (y + 54)^{2} = 73

将

(x + 92)^{2} + (y + 54)^{2} = 73

改写为圆标准方程

(x - (- 92))^{2} + (y - (- 54))^{2} = (73)^{2}

因此圆的性质是:

(a, b) = (- 92, - 54), r = 73

x^{2} - 4 x + y^{2} - 2 y = - 2

\frac{x ^{2}}{4} + \frac{y ^{2}}{64} = 1

f oc i \frac{( x - 7 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{100} = 1

y^{2} = 1 - x