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Beliebt Geometry >

foki y^2=28x

Lösung

foki

y^{2} = 28 x

Lösung

(7, 0)

Schritte zur Lösung

Rewrite

y^{2} = 28 x

in the standard form:

4 \cdot 7 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 7

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + 7, 0)

Fasse zusammen

(7, 0)

Graph

Beliebte Beispiele

3 x^{2} - 3 y = 0

foki (x^2)/(25)-(y^2)/(16)=1

f oc i \frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

scheitelpunkte f(x)=x^2-4x-5

v er t i ces f (x) = x^{2} - 4 x - 5

(y^2}{16}-\frac{x^2)/4 =1

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

x^{2} - 2 x + 8 y + 9 = 0