What is the foci y^2-(x^2)/9 =1 ?

The foci y^2-(x^2)/9 =1 is (0,sqrt(10)),(0,-sqrt(10))

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foci y^2-(x^2)/9 =1

foci

y^{2} - \frac{x ^{2}}{9} = 1

(0, 10), (0, - 10)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - \frac{x ^{2}}{9} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} + 3^{2} : 10

(0, 0 + 10), (0, 0 - 10)

Refine

(0, 10), (0, - 10)

y^{2} = 2 x + 1

x^{2} + 2 y^{2} = 3

f (x) = - x^{2} - 2 x + 2

x^{2} + 4 y^{2} - 4 x = 0

4 x^{2} + 9 y^{2} = 36

What is the foci y^2-(x^2)/9 =1 ?
The foci y^2-(x^2)/9 =1 is (0,sqrt(10)),(0,-sqrt(10))