What is the foci (x^2)/(25)+(y^2)/(25)=1 ?

The foci (x^2)/(25)+(y^2)/(25)=1 is (0,0),(0,0)

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foci (x^2)/(25)+(y^2)/(25)=1

foci

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

(0, 0), (0, 0)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} - 5^{2} : 0

(0, 0 + 0), (0, 0 - 0)

Refine

(0, 0), (0, 0)

y^{2} + 20 x + 8 y + 56 = 0

x^{2} + y^{2} \leq 16

f (x) = x^{2} + 4 x

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

2 x - y^{2} = 0

What is the foci (x^2)/(25)+(y^2)/(25)=1 ?
The foci (x^2)/(25)+(y^2)/(25)=1 is (0,0),(0,0)