f(x)(x)^{-1}=x+3

Lösung

f (x) (x)^{- 1} = x + 3

(h, k) = (- \frac{3}{2}, - \frac{9}{4}), p = \frac{1}{4}

Schritte zur Lösung

y x^{- 1} = x + 3

Rewrite

y x^{- 1} - x - 3 = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{9}{4})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{9}{4}), p = \frac{1}{4}

x^{2} + 2 z - 15 = 0

2 x^{2} + 92 = - 4 r (x)

25 y^{2} - x = 0

3 x^{2} + 2 x - 7 = O

(y + 3)^{2} = 2 (x - 4)