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Beliebt Geometry >

y^2+16x-4y+1=0

Lösung

y^{2} + 16 x - 4 y + 1 = 0

Lösung

(h, k) = (\frac{3}{16}, 2), p = - 4

Schritte zur Lösung

y^{2} + 16 x - 4 y + 1 = 0

Rewrite

y^{2} + 16 x - 4 y + 1 = 0

in the standard form

4 (- 4) (x - \frac{3}{16}) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{16}, 2), p = - 4

Graph

Beliebte Beispiele

y = - 4 x (x + 7)

x = - 3 (y - 5)^{2} + 1

(y-3)^2=-12(x-4)

(y - 3)^{2} = - 12 (x - 4)

x^{2} - 6 x + k (x) = 0

(x+5/4)^2=(h(x))/(16)

(x + \frac{5}{4})^{2} = \frac{h ( x )}{16}