x^2+x-12=izar

Lösung

x^{2} + x - 12 = i z a r

(h, k) = (0, (12 - x) i), p = \frac{i}{4}

Schritte zur Lösung

x^{2} + x - 12 = i z a r

Rewrite

x^{2} + x - 12 = i z a r

in the standard form

4 \cdot \frac{i}{4} (z - (12 - x) i) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, (12 - x) i), p = \frac{i}{4}

Y (x) + 1 = (x - 1)^{2}

x^{2} = 13 y

x^{2} + 2 \cdot 71 = o

x^{2} - 6 x - 10 y + 24 = 0

(y + 3)^{2} = 6 (x + 4)