y^2+x-36=0

Lösung

y^{2} + x - 36 = 0

(h, k) = (36, 0), p = - \frac{1}{4}

Schritte zur Lösung

y^{2} + x - 36 = 0

Rewrite

y^{2} + x - 36 = 0

in the standard form:

4 (- \frac{1}{4}) (x - 36) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (36, 0), p = - \frac{1}{4}

so l v e f or x, q (x)^{2} = (x + 20)

x^{2} + m (x) = 0

t^{2} - 10 r = - 7

x^{2} + 4 x - 8 y + 44 = 0

y > 2 x^{2} + 5