1/3 pir^2h=v

Lösung

\frac{1}{3} π r^{2} h = v

(h, k) = (0, 0), p = \frac{3}{4 πh}

Schritte zur Lösung

\frac{1}{3} π r^{2} h = v

Rewrite

\frac{1}{3} π r^{2} h = v

in the standard form:

4 \cdot \frac{3}{4 πh} (v - 0) = (r - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{3}{4 πh}

f (x) - 5 = x^{2} - 3 x + 2

x^{2} - 8 x + 4 y + 20 = 0

(x + 3)^{2} = 24 (y - 2)

y^{2} = \frac{4}{3} x

5 x^{2} - 4 x + P (x) = 0