What is the vertices x^2+9y^2+6x-90y+225=0 ?

The vertices x^2+9y^2+6x-90y+225=0 is (0,5),(-6,5)

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vertices x^2+9y^2+6x-90y+225=0

vertices

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0

(0, 5), (- 6, 5)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 9 y^{2} + 6 x - 90 y + 225 = 0 :

Ellipse with center

(h, k) = (- 3, 5), a = 3, b = 1

(- 3 + 3, 5), (- 3 - 3, 5)

Refine

(0, 5), (- 6, 5)

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{49} + \frac{y ^{2}}{9} = 1

y^{2} - x^{2} = 1

x^{2} + 4 y^{2} - 6 x + 20 y - 2 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

What is the vertices x^2+9y^2+6x-90y+225=0 ?
The vertices x^2+9y^2+6x-90y+225=0 is (0,5),(-6,5)