5x^2-x+3y+6=0

Lösung

5 x^{2} - x + 3 y + 6 = 0

(h, k) = (\frac{1}{10}, - \frac{119}{60}), p = - \frac{3}{20}

Schritte zur Lösung

5 x^{2} - x + 3 y + 6 = 0

Rewrite

5 x^{2} - x + 3 y + 6 = 0

in the standard form

4 (- \frac{3}{20}) (y - (- \frac{119}{60})) = (x - \frac{1}{10})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{10}, - \frac{119}{60}), p = - \frac{3}{20}

y 2 y = 10 x - 5

y^{2} - 3 z = 0

1 f (x) = 2 x^{2} + 8 x - 24

y^{2} + 12 x - 18 y = - 81

x^{2} - 6 x - 2 y + 11 = 0