x^2-4x+m(x)=0

Lösung

x^{2} - 4 x + m (x) = 0

(h, k) = (2, 4), p = - \frac{1}{4}

Schritte zur Lösung

x^{2} - 4 x + y = 0

Rewrite

x^{2} - 4 x + y = 0

in the standard form

4 (- \frac{1}{4}) (y - 4) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 4), p = - \frac{1}{4}

3 x^{2} - 6 x - 6 y + 10 = 0

A y^{2} - 6 x = 0

2 x + 2 y^{2} = 0

(y - 1)^{2} = - 16 (x + 4)

y^{2} - x + 3 = 0