y^2+2x-2y-3=0

Lösung

y^{2} + 2 x - 2 y - 3 = 0

(h, k) = (2, 1), p = - \frac{1}{2}

Schritte zur Lösung

y^{2} + 2 x - 2 y - 3 = 0

Rewrite

y^{2} + 2 x - 2 y - 3 = 0

in the standard form

4 (- \frac{1}{2}) (x - 2) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (2, 1), p = - \frac{1}{2}

x \frac{2}{3} x - 5 y = 2

x^{(2)} + 2 y = 0

y \frac{y}{12.5} = 3.5 + x

x^{2} - 4 x - y + 8 = 0

x - y^{2} = 6